[FX.php List] Simple JQuery question (I hope)

[Fitzgerald, Theodore C]

Bob,

You can add $('#submit').submit() like so:

$('#submit').click(function(){
                 $('.submitter').html('<div align="center"><img src="images/ajax-loader_large.gif"></div>');
                  $('#submit').submit();
 });

Ted

Application Developer
ITS-Enterprise Services
2800 UCC
University of Iowa

From: fx.php_list-bounces at mail.iviking.org [mailto:fx.php_list-bounces at mail.iviking.org] On Behalf Of Bob Patin
Sent: Friday, November 07, 2014 9:21 AM
To: FX.php Discussion List
Subject: [FX.php List] Simple JQuery question (I hope)

I have a POST form; when a user clicks the SUBMIT button, I want to replace the SUBMIT button with a spinning gear, so that users don’t click the button twice.

I’ve written this:

$('#submit').click(function(){
             $('.submitter').html('<div align="center"><img src="images/ajax-loader_large.gif"></div>');
 });


which works, but the form doesn’t submit; this seems to intercept the POST.

I tried adding this

$.post(‘card.php’) <—— card.php is the name of this form page

but it doesn’t make any difference.

Here is my question: how can I put the image into the DIV (which I’m doing above) and at the same time let the POST occur?

Thanks,

Bob Patin
Longterm Solutions
bob at longtermsolutions.com<mailto:bob at longtermsolutions.com>
615-333-6858
FileMaker 9, 10, 11, 12 & 13 Certified Developer
http://www.longtermsolutions.com
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